Metamath Proof Explorer


Theorem chfnrn

Description: The range of a choice function (a function that chooses an element from each member of its domain) is included in the union of its domain. (Contributed by NM, 31-Aug-1999)

Ref Expression
Assertion chfnrn ⊢ F Fn A ∧ ∀ x ∈ A F ⁡ x ∈ x → ran ⁡ F ⊆ ⋃ A

Proof

Step Hyp Ref Expression
1 fvelrnb ⊢ F Fn A → y ∈ ran ⁡ F ↔ ∃ x ∈ A F ⁡ x = y
2 1 biimpd ⊢ F Fn A → y ∈ ran ⁡ F → ∃ x ∈ A F ⁡ x = y
3 eleq1 ⊢ F ⁡ x = y → F ⁡ x ∈ x ↔ y ∈ x
4 3 biimpcd ⊢ F ⁡ x ∈ x → F ⁡ x = y → y ∈ x
5 4 ralimi ⊢ ∀ x ∈ A F ⁡ x ∈ x → ∀ x ∈ A F ⁡ x = y → y ∈ x
6 rexim ⊢ ∀ x ∈ A F ⁡ x = y → y ∈ x → ∃ x ∈ A F ⁡ x = y → ∃ x ∈ A y ∈ x
7 5 6 syl ⊢ ∀ x ∈ A F ⁡ x ∈ x → ∃ x ∈ A F ⁡ x = y → ∃ x ∈ A y ∈ x
8 2 7 sylan9 ⊢ F Fn A ∧ ∀ x ∈ A F ⁡ x ∈ x → y ∈ ran ⁡ F → ∃ x ∈ A y ∈ x
9 eluni2 ⊢ y ∈ ⋃ A ↔ ∃ x ∈ A y ∈ x
10 8 9 imbitrrdi ⊢ F Fn A ∧ ∀ x ∈ A F ⁡ x ∈ x → y ∈ ran ⁡ F → y ∈ ⋃ A
11 10 ssrdv ⊢ F Fn A ∧ ∀ x ∈ A F ⁡ x ∈ x → ran ⁡ F ⊆ ⋃ A