Theorem cnveqd

Description: Equality deduction for converse relation. (Contributed by NM, 6-Dec-2013)

	Ref	Expression
Hypothesis	cnveqd.1	$$⊢\phi \to A=B$$
Assertion	cnveqd	$$⊢\phi \to A^{-1}=B^{-1}$$

Proof

Step	Hyp	Ref	Expression
1		cnveqd.1	$$⊢\phi \to A=B$$
2		cnveq	$$⊢A=B\to A^{-1}=B^{-1}$$
3	1 2	syl	$$⊢\phi \to A^{-1}=B^{-1}$$