Metamath Proof Explorer


Theorem elcnv

Description: Membership in a converse relation. Equation 5 of Suppes p. 62. (Contributed by NM, 24-Mar-1998)

Ref Expression
Assertion elcnv ⊢ A ∈ R -1 ↔ ∃ x ∃ y A = x y ∧ y R x

Proof

Step Hyp Ref Expression
1 df-cnv ⊢ R -1 = x y | y R x
2 1 eleq2i ⊢ A ∈ R -1 ↔ A ∈ x y | y R x
3 elopab ⊢ A ∈ x y | y R x ↔ ∃ x ∃ y A = x y ∧ y R x
4 2 3 bitri ⊢ A ∈ R -1 ↔ ∃ x ∃ y A = x y ∧ y R x