Metamath Proof Explorer


Theorem coss1b

Description: Precomposition with a single-valued class (see cocnv2ssid ) preserves and reflects the subclass relation on its range. This is a generalization of the fact that surjections are right-cancellable. (Contributed by BJ, 24-Oct-2026) TODO: prove cocanss2 from it.

Ref Expression
Hypothesis coss1b.1 ⊢ φ → F ∘ F -1 ⊆ I
Assertion coss1b ⊢ φ → H ∘ F ⊆ K ∘ F ↔ H ↾ ran ⁡ F ⊆ K ↾ ran ⁡ F

Proof

Step Hyp Ref Expression
1 coss1b.1 ⊢ φ → F ∘ F -1 ⊆ I
2 coss1 ⊢ H ∘ F ⊆ K ∘ F → H ∘ F ∘ F -1 ⊆ K ∘ F ∘ F -1
3 coass ⊢ H ∘ F ∘ F -1 = H ∘ F ∘ F -1
4 iss ⊢ F ∘ F -1 ⊆ I ↔ F ∘ F -1 = I ↾ dom ⁡ F ∘ F -1
5 1 4 sylib ⊢ φ → F ∘ F -1 = I ↾ dom ⁡ F ∘ F -1
6 dmcocnv2 ⊢ dom ⁡ F ∘ F -1 = ran ⁡ F
7 6 reseq2i ⊢ I ↾ dom ⁡ F ∘ F -1 = I ↾ ran ⁡ F
8 5 7 eqtrdi ⊢ φ → F ∘ F -1 = I ↾ ran ⁡ F
9 8 coeq2d ⊢ φ → H ∘ F ∘ F -1 = H ∘ I ↾ ran ⁡ F
10 coires1 ⊢ H ∘ I ↾ ran ⁡ F = H ↾ ran ⁡ F
11 9 10 eqtrdi ⊢ φ → H ∘ F ∘ F -1 = H ↾ ran ⁡ F
12 3 11 eqtrid ⊢ φ → H ∘ F ∘ F -1 = H ↾ ran ⁡ F
13 coass ⊢ K ∘ F ∘ F -1 = K ∘ F ∘ F -1
14 8 coeq2d ⊢ φ → K ∘ F ∘ F -1 = K ∘ I ↾ ran ⁡ F
15 coires1 ⊢ K ∘ I ↾ ran ⁡ F = K ↾ ran ⁡ F
16 14 15 eqtrdi ⊢ φ → K ∘ F ∘ F -1 = K ↾ ran ⁡ F
17 13 16 eqtrid ⊢ φ → K ∘ F ∘ F -1 = K ↾ ran ⁡ F
18 12 17 sseq12d ⊢ φ → H ∘ F ∘ F -1 ⊆ K ∘ F ∘ F -1 ↔ H ↾ ran ⁡ F ⊆ K ↾ ran ⁡ F
19 2 18 imbitrid ⊢ φ → H ∘ F ⊆ K ∘ F → H ↾ ran ⁡ F ⊆ K ↾ ran ⁡ F
20 coss1 ⊢ H ↾ ran ⁡ F ⊆ K ↾ ran ⁡ F → H ↾ ran ⁡ F ∘ F ⊆ K ↾ ran ⁡ F ∘ F
21 coresrn ⊢ H ↾ ran ⁡ F ∘ F = H ∘ F
22 coresrn ⊢ K ↾ ran ⁡ F ∘ F = K ∘ F
23 20 21 22 3sstr3g ⊢ H ↾ ran ⁡ F ⊆ K ↾ ran ⁡ F → H ∘ F ⊆ K ∘ F
24 19 23 impbid1 ⊢ φ → H ∘ F ⊆ K ∘ F ↔ H ↾ ran ⁡ F ⊆ K ↾ ran ⁡ F