Metamath Proof Explorer


Theorem dfon2lem2

Description: Lemma for dfon2 . (Contributed by Scott Fenton, 28-Feb-2011)

Ref Expression
Assertion dfon2lem2 ⊢ ⋃ x | x ⊆ A ∧ φ ∧ ψ ⊆ A

Proof

Step Hyp Ref Expression
1 simp1 ⊢ x ⊆ A ∧ φ ∧ ψ → x ⊆ A
2 1 ss2abi ⊢ x | x ⊆ A ∧ φ ∧ ψ ⊆ x | x ⊆ A
3 df-pw ⊢ 𝒫 A = x | x ⊆ A
4 2 3 sseqtrri ⊢ x | x ⊆ A ∧ φ ∧ ψ ⊆ 𝒫 A
5 sspwuni ⊢ x | x ⊆ A ∧ φ ∧ ψ ⊆ 𝒫 A ↔ ⋃ x | x ⊆ A ∧ φ ∧ ψ ⊆ A
6 4 5 mpbi ⊢ ⋃ x | x ⊆ A ∧ φ ∧ ψ ⊆ A