Metamath Proof Explorer


Theorem dfon2lem2

Description: Lemma for dfon2 . (Contributed by Scott Fenton, 28-Feb-2011)

Ref Expression
Assertion dfon2lem2 ∪ { 𝑥 ∣ ( 𝑥 ⊆ 𝐴 ∧ 𝜑 ∧ 𝜓 ) } ⊆ 𝐴

Proof

Step Hyp Ref Expression
1 simp1 ⊢ ( ( 𝑥 ⊆ 𝐴 ∧ 𝜑 ∧ 𝜓 ) → 𝑥 ⊆ 𝐴 )
2 1 ss2abi ⊢ { 𝑥 ∣ ( 𝑥 ⊆ 𝐴 ∧ 𝜑 ∧ 𝜓 ) } ⊆ { 𝑥 ∣ 𝑥 ⊆ 𝐴 }
3 df-pw ⊢ 𝒫 𝐴 = { 𝑥 ∣ 𝑥 ⊆ 𝐴 }
4 2 3 sseqtrri ⊢ { 𝑥 ∣ ( 𝑥 ⊆ 𝐴 ∧ 𝜑 ∧ 𝜓 ) } ⊆ 𝒫 𝐴
5 sspwuni ⊢ ( { 𝑥 ∣ ( 𝑥 ⊆ 𝐴 ∧ 𝜑 ∧ 𝜓 ) } ⊆ 𝒫 𝐴 ↔ ∪ { 𝑥 ∣ ( 𝑥 ⊆ 𝐴 ∧ 𝜑 ∧ 𝜓 ) } ⊆ 𝐴 )
6 4 5 mpbi ⊢ ∪ { 𝑥 ∣ ( 𝑥 ⊆ 𝐴 ∧ 𝜑 ∧ 𝜓 ) } ⊆ 𝐴