Metamath Proof Explorer


Theorem dftpos5

Description: Alternate definition of tpos . (Contributed by Zhi Wang, 6-Oct-2025)

Ref Expression
Assertion dftpos5 ⊢ tpos F = F ∘ x ∈ dom ⁡ F -1 ⟼ ⋃ x -1 ∪ ∅ ∅

Proof

Step Hyp Ref Expression
1 df-tpos ⊢ tpos F = F ∘ x ∈ dom ⁡ F -1 ∪ ∅ ⟼ ⋃ x -1
2 mptun ⊢ x ∈ dom ⁡ F -1 ∪ ∅ ⟼ ⋃ x -1 = x ∈ dom ⁡ F -1 ⟼ ⋃ x -1 ∪ x ∈ ∅ ⟼ ⋃ x -1
3 0ex ⊢ ∅ ∈ V
4 sneq ⊢ x = ∅ → x = ∅
5 4 cnveqd ⊢ x = ∅ → x -1 = ∅ -1
6 5 unieqd ⊢ x = ∅ → ⋃ x -1 = ⋃ ∅ -1
7 cnvsn0 ⊢ ∅ -1 = ∅
8 7 unieqi ⊢ ⋃ ∅ -1 = ⋃ ∅
9 uni0 ⊢ ⋃ ∅ = ∅
10 8 9 eqtri ⊢ ⋃ ∅ -1 = ∅
11 6 10 eqtrdi ⊢ x = ∅ → ⋃ x -1 = ∅
12 11 fmptsng ⊢ ∅ ∈ V ∧ ∅ ∈ V → ∅ ∅ = x ∈ ∅ ⟼ ⋃ x -1
13 3 3 12 mp2an ⊢ ∅ ∅ = x ∈ ∅ ⟼ ⋃ x -1
14 13 uneq2i ⊢ x ∈ dom ⁡ F -1 ⟼ ⋃ x -1 ∪ ∅ ∅ = x ∈ dom ⁡ F -1 ⟼ ⋃ x -1 ∪ x ∈ ∅ ⟼ ⋃ x -1
15 2 14 eqtr4i ⊢ x ∈ dom ⁡ F -1 ∪ ∅ ⟼ ⋃ x -1 = x ∈ dom ⁡ F -1 ⟼ ⋃ x -1 ∪ ∅ ∅
16 15 coeq2i ⊢ F ∘ x ∈ dom ⁡ F -1 ∪ ∅ ⟼ ⋃ x -1 = F ∘ x ∈ dom ⁡ F -1 ⟼ ⋃ x -1 ∪ ∅ ∅
17 1 16 eqtri ⊢ tpos F = F ∘ x ∈ dom ⁡ F -1 ⟼ ⋃ x -1 ∪ ∅ ∅