Metamath Proof Explorer


Theorem dftpos5

Description: Alternate definition of tpos . (Contributed by Zhi Wang, 6-Oct-2025)

Ref Expression
Assertion dftpos5 tpos 𝐹 = ( 𝐹 ∘ ( ( 𝑥 ∈ ◡ dom 𝐹 ↦ ∪ ◡ { 𝑥 } ) ∪ { ⟨ ∅ , ∅ ⟩ } ) )

Proof

Step Hyp Ref Expression
1 df-tpos ⊢ tpos 𝐹 = ( 𝐹 ∘ ( 𝑥 ∈ ( ◡ dom 𝐹 ∪ { ∅ } ) ↦ ∪ ◡ { 𝑥 } ) )
2 mptun ⊢ ( 𝑥 ∈ ( ◡ dom 𝐹 ∪ { ∅ } ) ↦ ∪ ◡ { 𝑥 } ) = ( ( 𝑥 ∈ ◡ dom 𝐹 ↦ ∪ ◡ { 𝑥 } ) ∪ ( 𝑥 ∈ { ∅ } ↦ ∪ ◡ { 𝑥 } ) )
3 0ex ⊢ ∅ ∈ V
4 sneq ⊢ ( 𝑥 = ∅ → { 𝑥 } = { ∅ } )
5 4 cnveqd ⊢ ( 𝑥 = ∅ → ◡ { 𝑥 } = ◡ { ∅ } )
6 5 unieqd ⊢ ( 𝑥 = ∅ → ∪ ◡ { 𝑥 } = ∪ ◡ { ∅ } )
7 cnvsn0 ⊢ ◡ { ∅ } = ∅
8 7 unieqi ⊢ ∪ ◡ { ∅ } = ∪ ∅
9 uni0 ⊢ ∪ ∅ = ∅
10 8 9 eqtri ⊢ ∪ ◡ { ∅ } = ∅
11 6 10 eqtrdi ⊢ ( 𝑥 = ∅ → ∪ ◡ { 𝑥 } = ∅ )
12 11 fmptsng ⊢ ( ( ∅ ∈ V ∧ ∅ ∈ V ) → { ⟨ ∅ , ∅ ⟩ } = ( 𝑥 ∈ { ∅ } ↦ ∪ ◡ { 𝑥 } ) )
13 3 3 12 mp2an ⊢ { ⟨ ∅ , ∅ ⟩ } = ( 𝑥 ∈ { ∅ } ↦ ∪ ◡ { 𝑥 } )
14 13 uneq2i ⊢ ( ( 𝑥 ∈ ◡ dom 𝐹 ↦ ∪ ◡ { 𝑥 } ) ∪ { ⟨ ∅ , ∅ ⟩ } ) = ( ( 𝑥 ∈ ◡ dom 𝐹 ↦ ∪ ◡ { 𝑥 } ) ∪ ( 𝑥 ∈ { ∅ } ↦ ∪ ◡ { 𝑥 } ) )
15 2 14 eqtr4i ⊢ ( 𝑥 ∈ ( ◡ dom 𝐹 ∪ { ∅ } ) ↦ ∪ ◡ { 𝑥 } ) = ( ( 𝑥 ∈ ◡ dom 𝐹 ↦ ∪ ◡ { 𝑥 } ) ∪ { ⟨ ∅ , ∅ ⟩ } )
16 15 coeq2i ⊢ ( 𝐹 ∘ ( 𝑥 ∈ ( ◡ dom 𝐹 ∪ { ∅ } ) ↦ ∪ ◡ { 𝑥 } ) ) = ( 𝐹 ∘ ( ( 𝑥 ∈ ◡ dom 𝐹 ↦ ∪ ◡ { 𝑥 } ) ∪ { ⟨ ∅ , ∅ ⟩ } ) )
17 1 16 eqtri ⊢ tpos 𝐹 = ( 𝐹 ∘ ( ( 𝑥 ∈ ◡ dom 𝐹 ↦ ∪ ◡ { 𝑥 } ) ∪ { ⟨ ∅ , ∅ ⟩ } ) )