Metamath Proof Explorer


Theorem disj1

Description: Two ways of saying that two classes are disjoint (have no members in common). (Contributed by NM, 19-Aug-1993)

Ref Expression
Assertion disj1 ⊢ A ∩ B = ∅ ↔ ∀ x x ∈ A → ¬ x ∈ B

Proof

Step Hyp Ref Expression
1 disj ⊢ A ∩ B = ∅ ↔ ∀ x ∈ A ¬ x ∈ B
2 df-ral ⊢ ∀ x ∈ A ¬ x ∈ B ↔ ∀ x x ∈ A → ¬ x ∈ B
3 1 2 bitri ⊢ A ∩ B = ∅ ↔ ∀ x x ∈ A → ¬ x ∈ B