Metamath Proof Explorer


Theorem ditgeq123dv

Description: Equality theorem for the directed integral. Deduction form. General version of ditgeq3sdv . (Contributed by GG, 1-Sep-2025)

Ref Expression
Hypotheses ditgeq123dv.1 ⊢ φ → A = B
ditgeq123dv.2 ⊢ φ → C = D
ditgeq123dv.3 ⊢ φ → E = F
Assertion ditgeq123dv ⊢ φ → ∫ A C E dx = ∫ B D F dx

Proof

Step Hyp Ref Expression
1 ditgeq123dv.1 ⊢ φ → A = B
2 ditgeq123dv.2 ⊢ φ → C = D
3 ditgeq123dv.3 ⊢ φ → E = F
4 1 2 breq12d ⊢ φ → A ≤ C ↔ B ≤ D
5 1 2 oveq12d ⊢ φ → A C = B D
6 5 3 itgeq12sdv ⊢ φ → ∫ A C E dx = ∫ B D F dx
7 2 1 oveq12d ⊢ φ → C A = D B
8 7 3 itgeq12sdv ⊢ φ → ∫ C A E dx = ∫ D B F dx
9 8 negeqd ⊢ φ → − ∫ C A E dx = − ∫ D B F dx
10 4 6 9 ifbieq12d ⊢ φ → if A ≤ C ∫ A C E dx − ∫ C A E dx = if B ≤ D ∫ B D F dx − ∫ D B F dx
11 df-ditg ⊢ ∫ A C E dx = if A ≤ C ∫ A C E dx − ∫ C A E dx
12 df-ditg ⊢ ∫ B D F dx = if B ≤ D ∫ B D F dx − ∫ D B F dx
13 10 11 12 3eqtr4g ⊢ φ → ∫ A C E dx = ∫ B D F dx