Metamath Proof Explorer


Theorem dvelimh

Description: Version of dvelim without any variable restrictions. Usage of this theorem is discouraged because it depends on ax-13 . Check out dvelimhw for a version requiring fewer axioms. (Contributed by NM, 1-Oct-2002) (Proof shortened by Wolf Lammen, 11-May-2018) (New usage is discouraged.)

Ref Expression
Hypotheses dvelimh.1 φxφ
dvelimh.2 ψzψ
dvelimh.3 z=yφψ
Assertion dvelimh ¬xx=yψxψ

Proof

Step Hyp Ref Expression
1 dvelimh.1 φxφ
2 dvelimh.2 ψzψ
3 dvelimh.3 z=yφψ
4 1 nf5i xφ
5 2 nf5i zψ
6 4 5 3 dvelimf ¬xx=yxψ
7 6 nf5rd ¬xx=yψxψ