Metamath Proof Explorer


Theorem eleq1i

Description: Inference from equality to equivalence of membership. (Contributed by NM, 21-Jun-1993)

Ref Expression
Hypothesis eleq1i.1 A = B
Assertion eleq1i A C B C

Proof

Step Hyp Ref Expression
1 eleq1i.1 A = B
2 eleq1 A = B A C B C
3 1 2 ax-mp A C B C