Metamath Proof Explorer


Theorem ellspsn4

Description: A member of the span of the singleton of a vector is a member of a subspace containing the vector. ( elspansn4 analog.) (Contributed by NM, 4-Jul-2014)

Ref Expression
Hypotheses ellspsn4.v ⊢ V = Base W
ellspsn4.o ⊢ 0 ˙ = 0 W
ellspsn4.s ⊢ S = LSubSp ⁡ W
ellspsn4.n ⊢ N = LSpan ⁡ W
ellspsn4.w ⊢ φ → W ∈ LVec
ellspsn4.u ⊢ φ → U ∈ S
ellspsn4.x ⊢ φ → X ∈ V
ellspsn4.y ⊢ φ → Y ∈ N ⁡ X
ellspsn4.z ⊢ φ → Y ≠ 0 ˙
Assertion ellspsn4 ⊢ φ → X ∈ U ↔ Y ∈ U

Proof

Step Hyp Ref Expression
1 ellspsn4.v ⊢ V = Base W
2 ellspsn4.o ⊢ 0 ˙ = 0 W
3 ellspsn4.s ⊢ S = LSubSp ⁡ W
4 ellspsn4.n ⊢ N = LSpan ⁡ W
5 ellspsn4.w ⊢ φ → W ∈ LVec
6 ellspsn4.u ⊢ φ → U ∈ S
7 ellspsn4.x ⊢ φ → X ∈ V
8 ellspsn4.y ⊢ φ → Y ∈ N ⁡ X
9 ellspsn4.z ⊢ φ → Y ≠ 0 ˙
10 lveclmod ⊢ W ∈ LVec → W ∈ LMod
11 5 10 syl ⊢ φ → W ∈ LMod
12 11 adantr ⊢ φ ∧ X ∈ U → W ∈ LMod
13 6 adantr ⊢ φ ∧ X ∈ U → U ∈ S
14 simpr ⊢ φ ∧ X ∈ U → X ∈ U
15 8 adantr ⊢ φ ∧ X ∈ U → Y ∈ N ⁡ X
16 3 4 12 13 14 15 ellspsn3 ⊢ φ ∧ X ∈ U → Y ∈ U
17 11 adantr ⊢ φ ∧ Y ∈ U → W ∈ LMod
18 6 adantr ⊢ φ ∧ Y ∈ U → U ∈ S
19 simpr ⊢ φ ∧ Y ∈ U → Y ∈ U
20 1 4 lspsnid ⊢ W ∈ LMod ∧ X ∈ V → X ∈ N ⁡ X
21 11 7 20 syl2anc ⊢ φ → X ∈ N ⁡ X
22 1 2 4 5 7 8 9 lspsneleq ⊢ φ → N ⁡ Y = N ⁡ X
23 21 22 eleqtrrd ⊢ φ → X ∈ N ⁡ Y
24 23 adantr ⊢ φ ∧ Y ∈ U → X ∈ N ⁡ Y
25 3 4 17 18 19 24 ellspsn3 ⊢ φ ∧ Y ∈ U → X ∈ U
26 16 25 impbida ⊢ φ → X ∈ U ↔ Y ∈ U