Metamath Proof Explorer


Theorem elscottab

Description: An element of the output of the Scott operation applied to a class abstraction satisfies the class abstraction's predicate. (Contributed by Rohan Ridenour, 14-Aug-2023)

Ref Expression
Hypothesis elscottab.1 ⊢ x = y → φ ↔ ψ
Assertion elscottab ⊢ y ∈ Scott x | φ → ψ

Proof

Step Hyp Ref Expression
1 elscottab.1 ⊢ x = y → φ ↔ ψ
2 scottss ⊢ Scott x | φ ⊆ x | φ
3 2 sseli ⊢ y ∈ Scott x | φ → y ∈ x | φ
4 vex ⊢ y ∈ V
5 4 1 elab ⊢ y ∈ x | φ ↔ ψ
6 3 5 sylib ⊢ y ∈ Scott x | φ → ψ