Metamath Proof Explorer


Theorem elscottab

Description: An element of the output of the Scott operation applied to a class abstraction satisfies the class abstraction's predicate. (Contributed by Rohan Ridenour, 14-Aug-2023)

Ref Expression
Hypothesis elscottab.1 ⊢ ( 𝑥 = 𝑦 → ( 𝜑 ↔ 𝜓 ) )
Assertion elscottab ( 𝑦 ∈ Scott { 𝑥 ∣ 𝜑 } → 𝜓 )

Proof

Step Hyp Ref Expression
1 elscottab.1 ⊢ ( 𝑥 = 𝑦 → ( 𝜑 ↔ 𝜓 ) )
2 scottss ⊢ Scott { 𝑥 ∣ 𝜑 } ⊆ { 𝑥 ∣ 𝜑 }
3 2 sseli ⊢ ( 𝑦 ∈ Scott { 𝑥 ∣ 𝜑 } → 𝑦 ∈ { 𝑥 ∣ 𝜑 } )
4 vex ⊢ 𝑦 ∈ V
5 4 1 elab ⊢ ( 𝑦 ∈ { 𝑥 ∣ 𝜑 } ↔ 𝜓 )
6 3 5 sylib ⊢ ( 𝑦 ∈ Scott { 𝑥 ∣ 𝜑 } → 𝜓 )