Metamath Proof Explorer


Theorem evlsvval

Description: Give a formula for the evaluation of a polynomial. (Contributed by SN, 9-Feb-2025)

Ref Expression
Hypotheses evlsvval.q ⊢ Q = I evalSub S ⁡ R
evlsvval.p ⊢ P = I mPoly U
evlsvval.b ⊢ B = Base P
evlsvval.d ⊢ D = h ∈ ℕ 0 I | h -1 ℕ ∈ Fin
evlsvval.k ⊢ K = Base S
evlsvval.u ⊢ U = S ↾ 𝑠 R
evlsvval.t ⊢ T = S ↑ 𝑠 K I
evlsvval.m ⊢ M = mulGrp T
evlsvval.w ⊢ × ˙ = ⋅ M
evlsvval.x ⊢ · ˙ = ⋅ T
evlsvval.f ⊢ F = x ∈ R ⟼ K I × x
evlsvval.g ⊢ G = x ∈ I ⟼ a ∈ K I ⟼ a ⁡ x
evlsvval.i ⊢ φ → I ∈ V
evlsvval.s ⊢ φ → S ∈ CRing
evlsvval.r ⊢ φ → R ∈ SubRing ⁡ S
evlsvval.a ⊢ φ → A ∈ B
Assertion evlsvval ⊢ φ → Q ⁡ A = ∑ T b ∈ D F ⁡ A ⁡ b · ˙ ∑ M b × ˙ f G

Proof

Step Hyp Ref Expression
1 evlsvval.q ⊢ Q = I evalSub S ⁡ R
2 evlsvval.p ⊢ P = I mPoly U
3 evlsvval.b ⊢ B = Base P
4 evlsvval.d ⊢ D = h ∈ ℕ 0 I | h -1 ℕ ∈ Fin
5 evlsvval.k ⊢ K = Base S
6 evlsvval.u ⊢ U = S ↾ 𝑠 R
7 evlsvval.t ⊢ T = S ↑ 𝑠 K I
8 evlsvval.m ⊢ M = mulGrp T
9 evlsvval.w ⊢ × ˙ = ⋅ M
10 evlsvval.x ⊢ · ˙ = ⋅ T
11 evlsvval.f ⊢ F = x ∈ R ⟼ K I × x
12 evlsvval.g ⊢ G = x ∈ I ⟼ a ∈ K I ⟼ a ⁡ x
13 evlsvval.i ⊢ φ → I ∈ V
14 evlsvval.s ⊢ φ → S ∈ CRing
15 evlsvval.r ⊢ φ → R ∈ SubRing ⁡ S
16 evlsvval.a ⊢ φ → A ∈ B
17 fveq1 ⊢ p = A → p ⁡ b = A ⁡ b
18 17 fveq2d ⊢ p = A → F ⁡ p ⁡ b = F ⁡ A ⁡ b
19 18 oveq1d ⊢ p = A → F ⁡ p ⁡ b · ˙ ∑ M b × ˙ f G = F ⁡ A ⁡ b · ˙ ∑ M b × ˙ f G
20 19 mpteq2dv ⊢ p = A → b ∈ D ⟼ F ⁡ p ⁡ b · ˙ ∑ M b × ˙ f G = b ∈ D ⟼ F ⁡ A ⁡ b · ˙ ∑ M b × ˙ f G
21 20 oveq2d ⊢ p = A → ∑ T b ∈ D F ⁡ p ⁡ b · ˙ ∑ M b × ˙ f G = ∑ T b ∈ D F ⁡ A ⁡ b · ˙ ∑ M b × ˙ f G
22 eqid ⊢ p ∈ B ⟼ ∑ T b ∈ D F ⁡ p ⁡ b · ˙ ∑ M b × ˙ f G = p ∈ B ⟼ ∑ T b ∈ D F ⁡ p ⁡ b · ˙ ∑ M b × ˙ f G
23 1 2 3 4 5 6 7 8 9 10 22 11 12 13 14 15 evlsval3 ⊢ φ → Q = p ∈ B ⟼ ∑ T b ∈ D F ⁡ p ⁡ b · ˙ ∑ M b × ˙ f G
24 ovexd ⊢ φ → ∑ T b ∈ D F ⁡ A ⁡ b · ˙ ∑ M b × ˙ f G ∈ V
25 21 23 16 24 fvmptd4 ⊢ φ → Q ⁡ A = ∑ T b ∈ D F ⁡ A ⁡ b · ˙ ∑ M b × ˙ f G