Metamath Proof Explorer


Theorem evpmid

Description: The identity is an even permutation. (Contributed by Thierry Arnoux, 18-Sep-2023)

Ref Expression
Hypothesis evpmid.1 ⊢ S = SymGrp ⁡ D
Assertion evpmid ⊢ D ∈ Fin → I ↾ D ∈ pmEven ⁡ D

Proof

Step Hyp Ref Expression
1 evpmid.1 ⊢ S = SymGrp ⁡ D
2 1 idresperm ⊢ D ∈ Fin → I ↾ D ∈ Base S
3 eqid ⊢ pmSgn ⁡ D = pmSgn ⁡ D
4 3 psgnid ⊢ D ∈ Fin → pmSgn ⁡ D ⁡ I ↾ D = 1
5 eqid ⊢ Base S = Base S
6 1 5 3 psgnevpmb ⊢ D ∈ Fin → I ↾ D ∈ pmEven ⁡ D ↔ I ↾ D ∈ Base S ∧ pmSgn ⁡ D ⁡ I ↾ D = 1
7 2 4 6 mpbir2and ⊢ D ∈ Fin → I ↾ D ∈ pmEven ⁡ D