Metamath Proof Explorer


Theorem ex-exp

Description: Example for df-exp . (Contributed by AV, 4-Sep-2021)

Ref Expression
Assertion ex-exp ⊢ 5 2 = 25 ∧ − 3 − 2 = 1 9

Proof

Step Hyp Ref Expression
1 df-5 ⊢ 5 = 4 + 1
2 1 oveq1i ⊢ 5 2 = 4 + 1 2
3 4cn ⊢ 4 ∈ ℂ
4 binom21 ⊢ 4 ∈ ℂ → 4 + 1 2 = 4 2 + 2 ⋅ 4 + 1
5 3 4 ax-mp ⊢ 4 + 1 2 = 4 2 + 2 ⋅ 4 + 1
6 2nn0 ⊢ 2 ∈ ℕ 0
7 4nn0 ⊢ 4 ∈ ℕ 0
8 4p1e5 ⊢ 4 + 1 = 5
9 sq4e2t8 ⊢ 4 2 = 2 ⋅ 8
10 8cn ⊢ 8 ∈ ℂ
11 2cn ⊢ 2 ∈ ℂ
12 8t2e16 ⊢ 8 ⋅ 2 = 16
13 10 11 12 mulcomli ⊢ 2 ⋅ 8 = 16
14 9 13 eqtri ⊢ 4 2 = 16
15 2t4e8 ⊢ 2 ⋅ 4 = 8
16 14 15 oveq12i ⊢ 4 2 + 2 ⋅ 4 = 16 + 8
17 1nn0 ⊢ 1 ∈ ℕ 0
18 6nn0 ⊢ 6 ∈ ℕ 0
19 8nn0 ⊢ 8 ∈ ℕ 0
20 eqid ⊢ 16 = 16
21 1p1e2 ⊢ 1 + 1 = 2
22 6cn ⊢ 6 ∈ ℂ
23 8p6e14 ⊢ 8 + 6 = 14
24 10 22 23 addcomli ⊢ 6 + 8 = 14
25 17 18 19 20 21 7 24 decaddci ⊢ 16 + 8 = 24
26 16 25 eqtri ⊢ 4 2 + 2 ⋅ 4 = 24
27 6 7 8 26 decsuc ⊢ 4 2 + 2 ⋅ 4 + 1 = 25
28 5 27 eqtri ⊢ 4 + 1 2 = 25
29 2 28 eqtri ⊢ 5 2 = 25
30 3cn ⊢ 3 ∈ ℂ
31 30 negcli ⊢ − 3 ∈ ℂ
32 expneg ⊢ − 3 ∈ ℂ ∧ 2 ∈ ℕ 0 → − 3 − 2 = 1 − 3 2
33 31 6 32 mp2an ⊢ − 3 − 2 = 1 − 3 2
34 sqneg ⊢ 3 ∈ ℂ → − 3 2 = 3 2
35 30 34 ax-mp ⊢ − 3 2 = 3 2
36 sq3 ⊢ 3 2 = 9
37 35 36 eqtri ⊢ − 3 2 = 9
38 37 oveq2i ⊢ 1 − 3 2 = 1 9
39 33 38 eqtri ⊢ − 3 − 2 = 1 9
40 29 39 pm3.2i ⊢ 5 2 = 25 ∧ − 3 − 2 = 1 9