Metamath Proof Explorer


Theorem expdcom

Description: Commuted form of expd . (Contributed by Alan Sare, 18-Mar-2012) Shorten expd . (Revised by Wolf Lammen, 28-Jul-2022)

Ref Expression
Hypothesis expd.1 ⊢ φ → ψ ∧ χ → θ
Assertion expdcom ⊢ ψ → χ → φ → θ

Proof

Step Hyp Ref Expression
1 expd.1 ⊢ φ → ψ ∧ χ → θ
2 1 com12 ⊢ ψ ∧ χ → φ → θ
3 2 ex ⊢ ψ → χ → φ → θ