Metamath Proof Explorer


Theorem expsubd

Description: Exponent subtraction law for integer exponentiation. (Contributed by Mario Carneiro, 28-May-2016)

Ref Expression
Hypotheses expcld.1 ⊢ φ → A ∈ ℂ
sqrecd.1 ⊢ φ → A ≠ 0
expclzd.3 ⊢ φ → N ∈ ℤ
expsubd.3 ⊢ φ → M ∈ ℤ
Assertion expsubd ⊢ φ → A M − N = A M A N

Proof

Step Hyp Ref Expression
1 expcld.1 ⊢ φ → A ∈ ℂ
2 sqrecd.1 ⊢ φ → A ≠ 0
3 expclzd.3 ⊢ φ → N ∈ ℤ
4 expsubd.3 ⊢ φ → M ∈ ℤ
5 expsub ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ → A M − N = A M A N
6 1 2 4 3 5 syl22anc ⊢ φ → A M − N = A M A N