Metamath Proof Explorer


Theorem f1ocnvd

Description: Describe an implicit one-to-one onto function. (Contributed by Mario Carneiro, 30-Apr-2015)

Ref Expression
Hypotheses f1od.1 ⊢ F = x ∈ A ⟼ C
f1od.2 ⊢ φ ∧ x ∈ A → C ∈ W
f1od.3 ⊢ φ ∧ y ∈ B → D ∈ X
f1od.4 ⊢ φ → x ∈ A ∧ y = C ↔ y ∈ B ∧ x = D
Assertion f1ocnvd ⊢ φ → F : A ⟶ 1-1 onto B ∧ F -1 = y ∈ B ⟼ D

Proof

Step Hyp Ref Expression
1 f1od.1 ⊢ F = x ∈ A ⟼ C
2 f1od.2 ⊢ φ ∧ x ∈ A → C ∈ W
3 f1od.3 ⊢ φ ∧ y ∈ B → D ∈ X
4 f1od.4 ⊢ φ → x ∈ A ∧ y = C ↔ y ∈ B ∧ x = D
5 2 ralrimiva ⊢ φ → ∀ x ∈ A C ∈ W
6 1 fnmpt ⊢ ∀ x ∈ A C ∈ W → F Fn A
7 5 6 syl ⊢ φ → F Fn A
8 3 ralrimiva ⊢ φ → ∀ y ∈ B D ∈ X
9 eqid ⊢ y ∈ B ⟼ D = y ∈ B ⟼ D
10 9 fnmpt ⊢ ∀ y ∈ B D ∈ X → y ∈ B ⟼ D Fn B
11 8 10 syl ⊢ φ → y ∈ B ⟼ D Fn B
12 4 opabbidv ⊢ φ → y x | x ∈ A ∧ y = C = y x | y ∈ B ∧ x = D
13 df-mpt ⊢ x ∈ A ⟼ C = x y | x ∈ A ∧ y = C
14 1 13 eqtri ⊢ F = x y | x ∈ A ∧ y = C
15 14 cnveqi ⊢ F -1 = x y | x ∈ A ∧ y = C -1
16 cnvopab ⊢ x y | x ∈ A ∧ y = C -1 = y x | x ∈ A ∧ y = C
17 15 16 eqtri ⊢ F -1 = y x | x ∈ A ∧ y = C
18 df-mpt ⊢ y ∈ B ⟼ D = y x | y ∈ B ∧ x = D
19 12 17 18 3eqtr4g ⊢ φ → F -1 = y ∈ B ⟼ D
20 19 fneq1d ⊢ φ → F -1 Fn B ↔ y ∈ B ⟼ D Fn B
21 11 20 mpbird ⊢ φ → F -1 Fn B
22 dff1o4 ⊢ F : A ⟶ 1-1 onto B ↔ F Fn A ∧ F -1 Fn B
23 7 21 22 sylanbrc ⊢ φ → F : A ⟶ 1-1 onto B
24 23 19 jca ⊢ φ → F : A ⟶ 1-1 onto B ∧ F -1 = y ∈ B ⟼ D