Metamath Proof Explorer


Theorem f1oeq1

Description: Equality theorem for one-to-one onto functions. (Contributed by NM, 10-Feb-1997)

Ref Expression
Assertion f1oeq1 ⊢ F = G → F : A ⟶ 1-1 onto B ↔ G : A ⟶ 1-1 onto B

Proof

Step Hyp Ref Expression
1 f1eq1 ⊢ F = G → F : A ⟶ 1-1 B ↔ G : A ⟶ 1-1 B
2 foeq1 ⊢ F = G → F : A ⟶ onto B ↔ G : A ⟶ onto B
3 1 2 anbi12d ⊢ F = G → F : A ⟶ 1-1 B ∧ F : A ⟶ onto B ↔ G : A ⟶ 1-1 B ∧ G : A ⟶ onto B
4 df-f1o ⊢ F : A ⟶ 1-1 onto B ↔ F : A ⟶ 1-1 B ∧ F : A ⟶ onto B
5 df-f1o ⊢ G : A ⟶ 1-1 onto B ↔ G : A ⟶ 1-1 B ∧ G : A ⟶ onto B
6 3 4 5 3bitr4g ⊢ F = G → F : A ⟶ 1-1 onto B ↔ G : A ⟶ 1-1 onto B