Metamath Proof Explorer


Theorem f1omoOLD

Description: Obsolete version of f1omo as of 24-Nov-2025. (Contributed by Zhi Wang, 19-Sep-2024) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypothesis f1omo.1 ⊢ φ → F = A × 1 𝑜
Assertion f1omoOLD ⊢ φ → ∃* y y ∈ F ⁡ X

Proof

Step Hyp Ref Expression
1 f1omo.1 ⊢ φ → F = A × 1 𝑜
2 1oex ⊢ 1 𝑜 ∈ V
3 eqid ⊢ A × 1 𝑜 ⁡ X = A × 1 𝑜 ⁡ X
4 2 3 fvconst0ci ⊢ A × 1 𝑜 ⁡ X = ∅ ∨ A × 1 𝑜 ⁡ X = 1 𝑜
5 mo0 ⊢ A × 1 𝑜 ⁡ X = ∅ → ∃* y y ∈ A × 1 𝑜 ⁡ X
6 el1o ⊢ y ∈ 1 𝑜 ↔ y = ∅
7 el1o ⊢ x ∈ 1 𝑜 ↔ x = ∅
8 eqtr3 ⊢ y = ∅ ∧ x = ∅ → y = x
9 6 7 8 syl2anb ⊢ y ∈ 1 𝑜 ∧ x ∈ 1 𝑜 → y = x
10 9 gen2 ⊢ ∀ y ∀ x y ∈ 1 𝑜 ∧ x ∈ 1 𝑜 → y = x
11 eleq1w ⊢ y = x → y ∈ 1 𝑜 ↔ x ∈ 1 𝑜
12 11 mo4 ⊢ ∃* y y ∈ 1 𝑜 ↔ ∀ y ∀ x y ∈ 1 𝑜 ∧ x ∈ 1 𝑜 → y = x
13 10 12 mpbir ⊢ ∃* y y ∈ 1 𝑜
14 eleq2w2 ⊢ A × 1 𝑜 ⁡ X = 1 𝑜 → y ∈ A × 1 𝑜 ⁡ X ↔ y ∈ 1 𝑜
15 14 mobidv ⊢ A × 1 𝑜 ⁡ X = 1 𝑜 → ∃* y y ∈ A × 1 𝑜 ⁡ X ↔ ∃* y y ∈ 1 𝑜
16 13 15 mpbiri ⊢ A × 1 𝑜 ⁡ X = 1 𝑜 → ∃* y y ∈ A × 1 𝑜 ⁡ X
17 5 16 jaoi ⊢ A × 1 𝑜 ⁡ X = ∅ ∨ A × 1 𝑜 ⁡ X = 1 𝑜 → ∃* y y ∈ A × 1 𝑜 ⁡ X
18 4 17 ax-mp ⊢ ∃* y y ∈ A × 1 𝑜 ⁡ X
19 1 fveq1d ⊢ φ → F ⁡ X = A × 1 𝑜 ⁡ X
20 19 eleq2d ⊢ φ → y ∈ F ⁡ X ↔ y ∈ A × 1 𝑜 ⁡ X
21 20 mobidv ⊢ φ → ∃* y y ∈ F ⁡ X ↔ ∃* y y ∈ A × 1 𝑜 ⁡ X
22 18 21 mpbiri ⊢ φ → ∃* y y ∈ F ⁡ X