Metamath Proof Explorer


Theorem feq123d

Description: Equality deduction for functions. (Contributed by Paul Chapman, 22-Jun-2011)

Ref Expression
Hypotheses feq12d.1 ⊢ φ → F = G
feq12d.2 ⊢ φ → A = B
feq123d.3 ⊢ φ → C = D
Assertion feq123d ⊢ φ → F : A ⟶ C ↔ G : B ⟶ D

Proof

Step Hyp Ref Expression
1 feq12d.1 ⊢ φ → F = G
2 feq12d.2 ⊢ φ → A = B
3 feq123d.3 ⊢ φ → C = D
4 1 2 feq12d ⊢ φ → F : A ⟶ C ↔ G : B ⟶ C
5 3 feq3d ⊢ φ → G : B ⟶ C ↔ G : B ⟶ D
6 4 5 bitrd ⊢ φ → F : A ⟶ C ↔ G : B ⟶ D