Metamath Proof Explorer


Theorem fmtno0

Description: The 0 th Fermat number, see remark in ApostolNT p. 7. (Contributed by AV, 13-Jun-2021)

Ref Expression
Assertion fmtno0 ⊢ FermatNo ⁡ 0 = 3

Proof

Step Hyp Ref Expression
1 0nn0 ⊢ 0 ∈ ℕ 0
2 fmtno ⊢ 0 ∈ ℕ 0 → FermatNo ⁡ 0 = 2 2 0 + 1
3 1 2 ax-mp ⊢ FermatNo ⁡ 0 = 2 2 0 + 1
4 2cn ⊢ 2 ∈ ℂ
5 exp0 ⊢ 2 ∈ ℂ → 2 0 = 1
6 4 5 ax-mp ⊢ 2 0 = 1
7 6 oveq2i ⊢ 2 2 0 = 2 1
8 7 oveq1i ⊢ 2 2 0 + 1 = 2 1 + 1
9 exp1 ⊢ 2 ∈ ℂ → 2 1 = 2
10 4 9 ax-mp ⊢ 2 1 = 2
11 10 oveq1i ⊢ 2 1 + 1 = 2 + 1
12 2p1e3 ⊢ 2 + 1 = 3
13 8 11 12 3eqtri ⊢ 2 2 0 + 1 = 3
14 3 13 eqtri ⊢ FermatNo ⁡ 0 = 3