Metamath Proof Explorer


Theorem fovcl

Description: Closure law for an operation. (Contributed by NM, 19-Apr-2007) (Proof shortened by AV, 9-Mar-2025)

Ref Expression
Hypothesis fovcl.1 ⊢ F : R × S ⟶ C
Assertion fovcl ⊢ A ∈ R ∧ B ∈ S → A F B ∈ C

Proof

Step Hyp Ref Expression
1 fovcl.1 ⊢ F : R × S ⟶ C
2 1 a1i ⊢ A ∈ R → F : R × S ⟶ C
3 2 fovcld ⊢ A ∈ R ∧ A ∈ R ∧ B ∈ S → A F B ∈ C
4 3 3anidm12 ⊢ A ∈ R ∧ B ∈ S → A F B ∈ C