Metamath Proof Explorer


Theorem frege55b

Description: Lemma for frege57b . Proposition 55 of Frege1879 p. 50.

Note that eqtr2 incorporates eqcom which is stronger than this proposition which is identical to equcomi . Is it possible that Frege tricked himself into assuming what he was out to prove? (Contributed by RP, 24-Dec-2019) (Proof modification is discouraged.)

Ref Expression
Assertion frege55b x = y y = x

Proof

Step Hyp Ref Expression
1 frege55lem2b x = y y z z = x
2 dfsb1 y z z = x z = y z = x z z = y z = x
3 eqtr2 z = y z = x y = x
4 3 exlimiv z z = y z = x y = x
5 4 adantl z = y z = x z z = y z = x y = x
6 2 5 sylbi y z z = x y = x
7 1 6 syl x = y y = x