Description: Lemma for frege57b . Proposition 55 of Frege1879 p. 50.
Note that eqtr2 incorporates eqcom which is stronger than this proposition which is identical to equcomi . Is it possible that Frege tricked himself into assuming what he was out to prove? (Contributed by RP, 24-Dec-2019) (Proof modification is discouraged.)
Ref | Expression | ||
---|---|---|---|
Assertion | frege55b | |- ( x = y -> y = x ) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | frege55lem2b | |- ( x = y -> [ y / z ] z = x ) |
|
2 | dfsb1 | |- ( [ y / z ] z = x <-> ( ( z = y -> z = x ) /\ E. z ( z = y /\ z = x ) ) ) |
|
3 | eqtr2 | |- ( ( z = y /\ z = x ) -> y = x ) |
|
4 | 3 | exlimiv | |- ( E. z ( z = y /\ z = x ) -> y = x ) |
5 | 4 | adantl | |- ( ( ( z = y -> z = x ) /\ E. z ( z = y /\ z = x ) ) -> y = x ) |
6 | 2 5 | sylbi | |- ( [ y / z ] z = x -> y = x ) |
7 | 1 6 | syl | |- ( x = y -> y = x ) |