Metamath Proof Explorer


Theorem frege55b

Description: Lemma for frege57b . Proposition 55 of Frege1879 p. 50.

Note that eqtr2 incorporates eqcom which is stronger than this proposition which is identical to equcomi . Is it possible that Frege tricked himself into assuming what he was out to prove? (Contributed by RP, 24-Dec-2019) (Proof modification is discouraged.)

Ref Expression
Assertion frege55b
|- ( x = y -> y = x )

Proof

Step Hyp Ref Expression
1 frege55lem2b
 |-  ( x = y -> [ y / z ] z = x )
2 dfsb1
 |-  ( [ y / z ] z = x <-> ( ( z = y -> z = x ) /\ E. z ( z = y /\ z = x ) ) )
3 eqtr2
 |-  ( ( z = y /\ z = x ) -> y = x )
4 3 exlimiv
 |-  ( E. z ( z = y /\ z = x ) -> y = x )
5 4 adantl
 |-  ( ( ( z = y -> z = x ) /\ E. z ( z = y /\ z = x ) ) -> y = x )
6 2 5 sylbi
 |-  ( [ y / z ] z = x -> y = x )
7 1 6 syl
 |-  ( x = y -> y = x )