Metamath Proof Explorer


Theorem frege55b

Description: Lemma for frege57b . Proposition 55 of Frege1879 p. 50.

Note that eqtr2 incorporates eqcom which is stronger than this proposition which is identical to equcomi . Is it possible that Frege tricked himself into assuming what he was out to prove? (Contributed by RP, 24-Dec-2019) (Proof modification is discouraged.)

Ref Expression
Assertion frege55b ( 𝑥 = 𝑦𝑦 = 𝑥 )

Proof

Step Hyp Ref Expression
1 frege55lem2b ( 𝑥 = 𝑦 → [ 𝑦 / 𝑧 ] 𝑧 = 𝑥 )
2 dfsb1 ( [ 𝑦 / 𝑧 ] 𝑧 = 𝑥 ↔ ( ( 𝑧 = 𝑦𝑧 = 𝑥 ) ∧ ∃ 𝑧 ( 𝑧 = 𝑦𝑧 = 𝑥 ) ) )
3 eqtr2 ( ( 𝑧 = 𝑦𝑧 = 𝑥 ) → 𝑦 = 𝑥 )
4 3 exlimiv ( ∃ 𝑧 ( 𝑧 = 𝑦𝑧 = 𝑥 ) → 𝑦 = 𝑥 )
5 4 adantl ( ( ( 𝑧 = 𝑦𝑧 = 𝑥 ) ∧ ∃ 𝑧 ( 𝑧 = 𝑦𝑧 = 𝑥 ) ) → 𝑦 = 𝑥 )
6 2 5 sylbi ( [ 𝑦 / 𝑧 ] 𝑧 = 𝑥𝑦 = 𝑥 )
7 1 6 syl ( 𝑥 = 𝑦𝑦 = 𝑥 )