Description: Lemma for frege57b . Proposition 55 of Frege1879 p. 50.
Note that eqtr2 incorporates eqcom which is stronger than this proposition which is identical to equcomi . Is it possible that Frege tricked himself into assuming what he was out to prove? (Contributed by RP, 24-Dec-2019) (Proof modification is discouraged.)
Ref | Expression | ||
---|---|---|---|
Assertion | frege55b | ⊢ ( 𝑥 = 𝑦 → 𝑦 = 𝑥 ) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | frege55lem2b | ⊢ ( 𝑥 = 𝑦 → [ 𝑦 / 𝑧 ] 𝑧 = 𝑥 ) | |
2 | dfsb1 | ⊢ ( [ 𝑦 / 𝑧 ] 𝑧 = 𝑥 ↔ ( ( 𝑧 = 𝑦 → 𝑧 = 𝑥 ) ∧ ∃ 𝑧 ( 𝑧 = 𝑦 ∧ 𝑧 = 𝑥 ) ) ) | |
3 | eqtr2 | ⊢ ( ( 𝑧 = 𝑦 ∧ 𝑧 = 𝑥 ) → 𝑦 = 𝑥 ) | |
4 | 3 | exlimiv | ⊢ ( ∃ 𝑧 ( 𝑧 = 𝑦 ∧ 𝑧 = 𝑥 ) → 𝑦 = 𝑥 ) |
5 | 4 | adantl | ⊢ ( ( ( 𝑧 = 𝑦 → 𝑧 = 𝑥 ) ∧ ∃ 𝑧 ( 𝑧 = 𝑦 ∧ 𝑧 = 𝑥 ) ) → 𝑦 = 𝑥 ) |
6 | 2 5 | sylbi | ⊢ ( [ 𝑦 / 𝑧 ] 𝑧 = 𝑥 → 𝑦 = 𝑥 ) |
7 | 1 6 | syl | ⊢ ( 𝑥 = 𝑦 → 𝑦 = 𝑥 ) |