Metamath Proof Explorer


Theorem frege56b

Description: Lemma for frege57b . Proposition 56 of Frege1879 p. 50. (Contributed by RP, 24-Dec-2019) (Proof modification is discouraged.)

Ref Expression
Assertion frege56b ( ( 𝑥 = 𝑦 → ( [ 𝑥 / 𝑧 ] 𝜑 → [ 𝑦 / 𝑧 ] 𝜑 ) ) → ( 𝑦 = 𝑥 → ( [ 𝑥 / 𝑧 ] 𝜑 → [ 𝑦 / 𝑧 ] 𝜑 ) ) )

Proof

Step Hyp Ref Expression
1 frege55b ( 𝑦 = 𝑥𝑥 = 𝑦 )
2 frege9 ( ( 𝑦 = 𝑥𝑥 = 𝑦 ) → ( ( 𝑥 = 𝑦 → ( [ 𝑥 / 𝑧 ] 𝜑 → [ 𝑦 / 𝑧 ] 𝜑 ) ) → ( 𝑦 = 𝑥 → ( [ 𝑥 / 𝑧 ] 𝜑 → [ 𝑦 / 𝑧 ] 𝜑 ) ) ) )
3 1 2 ax-mp ( ( 𝑥 = 𝑦 → ( [ 𝑥 / 𝑧 ] 𝜑 → [ 𝑦 / 𝑧 ] 𝜑 ) ) → ( 𝑦 = 𝑥 → ( [ 𝑥 / 𝑧 ] 𝜑 → [ 𝑦 / 𝑧 ] 𝜑 ) ) )