Metamath Proof Explorer


Theorem frege55b

Description: Lemma for frege57b . Proposition 55 of Frege1879 p. 50.

Note that eqtr2 incorporates eqcom which is stronger than this proposition which is identical to equcomi . Is it possible that Frege tricked himself into assuming what he was out to prove? (Contributed by RP, 24-Dec-2019) (Proof modification is discouraged.)

Ref Expression
Assertion frege55b ⊢ x = y → y = x

Proof

Step Hyp Ref Expression
1 frege55lem2b ⊢ x = y → y z z = x
2 dfsb1 ⊢ y z z = x ↔ z = y → z = x ∧ ∃ z z = y ∧ z = x
3 eqtr2 ⊢ z = y ∧ z = x → y = x
4 3 exlimiv ⊢ ∃ z z = y ∧ z = x → y = x
5 4 adantl ⊢ z = y → z = x ∧ ∃ z z = y ∧ z = x → y = x
6 2 5 sylbi ⊢ y z z = x → y = x
7 1 6 syl ⊢ x = y → y = x