Metamath Proof Explorer


Theorem fvopab4ndm

Description: Value of a function given by an ordered-pair class abstraction, outside of its domain. (Contributed by NM, 28-Mar-2008)

Ref Expression
Hypothesis fvopab4ndm.1 ⊢ F = x y | x ∈ A ∧ φ
Assertion fvopab4ndm ⊢ ¬ B ∈ A → F ⁡ B = ∅

Proof

Step Hyp Ref Expression
1 fvopab4ndm.1 ⊢ F = x y | x ∈ A ∧ φ
2 1 dmeqi ⊢ dom ⁡ F = dom ⁡ x y | x ∈ A ∧ φ
3 dmopabss ⊢ dom ⁡ x y | x ∈ A ∧ φ ⊆ A
4 2 3 eqsstri ⊢ dom ⁡ F ⊆ A
5 4 sseli ⊢ B ∈ dom ⁡ F → B ∈ A
6 ndmfv ⊢ ¬ B ∈ dom ⁡ F → F ⁡ B = ∅
7 5 6 nsyl5 ⊢ ¬ B ∈ A → F ⁡ B = ∅