Metamath Proof Explorer


Theorem fvpr2g

Description: The value of a function with a domain of (at most) two elements. (Contributed by Alexander van der Vekens, 3-Dec-2017) (Proof shortened by BJ, 26-Sep-2024)

Ref Expression
Assertion fvpr2g ⊢ B ∈ V ∧ D ∈ W ∧ A ≠ B → A C B D ⁡ B = D

Proof

Step Hyp Ref Expression
1 prcom ⊢ A C B D = B D A C
2 1 fveq1i ⊢ A C B D ⁡ B = B D A C ⁡ B
3 necom ⊢ A ≠ B ↔ B ≠ A
4 fvpr1g ⊢ B ∈ V ∧ D ∈ W ∧ B ≠ A → B D A C ⁡ B = D
5 3 4 syl3an3b ⊢ B ∈ V ∧ D ∈ W ∧ A ≠ B → B D A C ⁡ B = D
6 2 5 eqtrid ⊢ B ∈ V ∧ D ∈ W ∧ A ≠ B → A C B D ⁡ B = D