Metamath Proof Explorer


Theorem fvtp1g

Description: The value of a function with a domain of (at most) three elements. (Contributed by Alexander van der Vekens, 4-Dec-2017)

Ref Expression
Assertion fvtp1g ⊢ A ∈ V ∧ D ∈ W ∧ A ≠ B ∧ A ≠ C → A D B E C F ⁡ A = D

Proof

Step Hyp Ref Expression
1 df-tp ⊢ A D B E C F = A D B E ∪ C F
2 1 fveq1i ⊢ A D B E C F ⁡ A = A D B E ∪ C F ⁡ A
3 necom ⊢ A ≠ C ↔ C ≠ A
4 fvunsn ⊢ C ≠ A → A D B E ∪ C F ⁡ A = A D B E ⁡ A
5 3 4 sylbi ⊢ A ≠ C → A D B E ∪ C F ⁡ A = A D B E ⁡ A
6 5 ad2antll ⊢ A ∈ V ∧ D ∈ W ∧ A ≠ B ∧ A ≠ C → A D B E ∪ C F ⁡ A = A D B E ⁡ A
7 fvpr1g ⊢ A ∈ V ∧ D ∈ W ∧ A ≠ B → A D B E ⁡ A = D
8 7 3expa ⊢ A ∈ V ∧ D ∈ W ∧ A ≠ B → A D B E ⁡ A = D
9 8 adantrr ⊢ A ∈ V ∧ D ∈ W ∧ A ≠ B ∧ A ≠ C → A D B E ⁡ A = D
10 6 9 eqtrd ⊢ A ∈ V ∧ D ∈ W ∧ A ≠ B ∧ A ≠ C → A D B E ∪ C F ⁡ A = D
11 2 10 eqtrid ⊢ A ∈ V ∧ D ∈ W ∧ A ≠ B ∧ A ≠ C → A D B E C F ⁡ A = D