Metamath Proof Explorer


Theorem ghmabl

Description: The image of an abelian group G under a group homomorphism F is an abelian group. (Contributed by Mario Carneiro, 12-May-2014) (Revised by Thierry Arnoux, 26-Jan-2020)

Ref Expression
Hypotheses ghmabl.x ⊢ X = Base G
ghmabl.y ⊢ Y = Base H
ghmabl.p ⊢ + ˙ = + G
ghmabl.q ⊢ ⨣ ˙ = + H
ghmabl.f ⊢ φ ∧ x ∈ X ∧ y ∈ X → F ⁡ x + ˙ y = F ⁡ x ⨣ ˙ F ⁡ y
ghmabl.1 ⊢ φ → F : X ⟶ onto Y
ghmabl.3 ⊢ φ → G ∈ Abel
Assertion ghmabl ⊢ φ → H ∈ Abel

Proof

Step Hyp Ref Expression
1 ghmabl.x ⊢ X = Base G
2 ghmabl.y ⊢ Y = Base H
3 ghmabl.p ⊢ + ˙ = + G
4 ghmabl.q ⊢ ⨣ ˙ = + H
5 ghmabl.f ⊢ φ ∧ x ∈ X ∧ y ∈ X → F ⁡ x + ˙ y = F ⁡ x ⨣ ˙ F ⁡ y
6 ghmabl.1 ⊢ φ → F : X ⟶ onto Y
7 ghmabl.3 ⊢ φ → G ∈ Abel
8 ablgrp ⊢ G ∈ Abel → G ∈ Grp
9 7 8 syl ⊢ φ → G ∈ Grp
10 5 1 2 3 4 6 9 ghmgrp ⊢ φ → H ∈ Grp
11 ablcmn ⊢ G ∈ Abel → G ∈ CMnd
12 7 11 syl ⊢ φ → G ∈ CMnd
13 1 2 3 4 5 6 12 ghmcmn ⊢ φ → H ∈ CMnd
14 isabl ⊢ H ∈ Abel ↔ H ∈ Grp ∧ H ∈ CMnd
15 10 13 14 sylanbrc ⊢ φ → H ∈ Abel