Metamath Proof Explorer


Theorem grpsubf

Description: Functionality of group subtraction. (Contributed by Mario Carneiro, 9-Sep-2014)

Ref Expression
Hypotheses grpsubcl.b ⊢ B = Base G
grpsubcl.m ⊢ - ˙ = - G
Assertion grpsubf ⊢ G ∈ Grp → - ˙ : B × B ⟶ B

Proof

Step Hyp Ref Expression
1 grpsubcl.b ⊢ B = Base G
2 grpsubcl.m ⊢ - ˙ = - G
3 eqid ⊢ inv g ⁡ G = inv g ⁡ G
4 1 3 grpinvcl ⊢ G ∈ Grp ∧ y ∈ B → inv g ⁡ G ⁡ y ∈ B
5 4 3adant2 ⊢ G ∈ Grp ∧ x ∈ B ∧ y ∈ B → inv g ⁡ G ⁡ y ∈ B
6 eqid ⊢ + G = + G
7 1 6 grpcl ⊢ G ∈ Grp ∧ x ∈ B ∧ inv g ⁡ G ⁡ y ∈ B → x + G inv g ⁡ G ⁡ y ∈ B
8 5 7 syld3an3 ⊢ G ∈ Grp ∧ x ∈ B ∧ y ∈ B → x + G inv g ⁡ G ⁡ y ∈ B
9 8 3expb ⊢ G ∈ Grp ∧ x ∈ B ∧ y ∈ B → x + G inv g ⁡ G ⁡ y ∈ B
10 9 ralrimivva ⊢ G ∈ Grp → ∀ x ∈ B ∀ y ∈ B x + G inv g ⁡ G ⁡ y ∈ B
11 1 6 3 2 grpsubfval ⊢ - ˙ = x ∈ B , y ∈ B ⟼ x + G inv g ⁡ G ⁡ y
12 11 fmpo ⊢ ∀ x ∈ B ∀ y ∈ B x + G inv g ⁡ G ⁡ y ∈ B ↔ - ˙ : B × B ⟶ B
13 10 12 sylib ⊢ G ∈ Grp → - ˙ : B × B ⟶ B