Metamath Proof Explorer


Theorem gsum0

Description: Value of the empty group sum. (Contributed by Mario Carneiro, 7-Dec-2014)

Ref Expression
Hypothesis gsum0.z ⊢ 0 ˙ = 0 G
Assertion gsum0 ⊢ ∑ G ∅ = 0 ˙

Proof

Step Hyp Ref Expression
1 gsum0.z ⊢ 0 ˙ = 0 G
2 eqid ⊢ Base G = Base G
3 eqid ⊢ + G = + G
4 eqid ⊢ x ∈ Base G | ∀ y ∈ Base G x + G y = y ∧ y + G x = y = x ∈ Base G | ∀ y ∈ Base G x + G y = y ∧ y + G x = y
5 id ⊢ G ∈ V → G ∈ V
6 0ex ⊢ ∅ ∈ V
7 6 a1i ⊢ G ∈ V → ∅ ∈ V
8 f0 ⊢ ∅ : ∅ ⟶ x ∈ Base G | ∀ y ∈ Base G x + G y = y ∧ y + G x = y
9 8 a1i ⊢ G ∈ V → ∅ : ∅ ⟶ x ∈ Base G | ∀ y ∈ Base G x + G y = y ∧ y + G x = y
10 2 1 3 4 5 7 9 gsumval1 ⊢ G ∈ V → ∑ G ∅ = 0 ˙
11 df-gsum ⊢ Σ𝑔 = w ∈ V , f ∈ V ⟼ ⦋ x ∈ Base w | ∀ y ∈ Base w x + w y = y ∧ y + w x = y / o⦌ if ran ⁡ f ⊆ o 0 w if dom ⁡ f ∈ ran ⁡ … ι x | ∃ m ∃ n ∈ ℤ ≥ m dom ⁡ f = m … n ∧ x = seq m + w f ⁡ n ι x | ∃ g [˙ f -1 V ∖ o / y]˙ g : 1 … y ⟶ 1-1 onto y ∧ x = seq 1 + w f ∘ g ⁡ y
12 11 reldmmpo ⊢ Rel ⁡ dom ⁡ Σ𝑔
13 12 ovprc1 ⊢ ¬ G ∈ V → ∑ G ∅ = ∅
14 fvprc ⊢ ¬ G ∈ V → 0 G = ∅
15 1 14 eqtrid ⊢ ¬ G ∈ V → 0 ˙ = ∅
16 13 15 eqtr4d ⊢ ¬ G ∈ V → ∑ G ∅ = 0 ˙
17 10 16 pm2.61i ⊢ ∑ G ∅ = 0 ˙