Metamath Proof Explorer


Theorem gsumsplit2f

Description: Split a group sum into two parts. (Contributed by AV, 4-Sep-2019)

Ref Expression
Hypotheses gsumsplit2f.n ⊢ Ⅎ k φ
gsumsplit2f.b ⊢ B = Base G
gsumsplit2f.z ⊢ 0 ˙ = 0 G
gsumsplit2f.p ⊢ + ˙ = + G
gsumsplit2f.g ⊢ φ → G ∈ CMnd
gsumsplit2f.a ⊢ φ → A ∈ V
gsumsplit2f.f ⊢ φ ∧ k ∈ A → X ∈ B
gsumsplit2f.w ⊢ φ → finSupp 0 ˙⁡ k ∈ A ⟼ X
gsumsplit2f.i ⊢ φ → C ∩ D = ∅
gsumsplit2f.u ⊢ φ → A = C ∪ D
Assertion gsumsplit2f ⊢ φ → ∑ G k ∈ A X = ∑ G k ∈ C X + ˙ ∑ G k ∈ D X

Proof

Step Hyp Ref Expression
1 gsumsplit2f.n ⊢ Ⅎ k φ
2 gsumsplit2f.b ⊢ B = Base G
3 gsumsplit2f.z ⊢ 0 ˙ = 0 G
4 gsumsplit2f.p ⊢ + ˙ = + G
5 gsumsplit2f.g ⊢ φ → G ∈ CMnd
6 gsumsplit2f.a ⊢ φ → A ∈ V
7 gsumsplit2f.f ⊢ φ ∧ k ∈ A → X ∈ B
8 gsumsplit2f.w ⊢ φ → finSupp 0 ˙⁡ k ∈ A ⟼ X
9 gsumsplit2f.i ⊢ φ → C ∩ D = ∅
10 gsumsplit2f.u ⊢ φ → A = C ∪ D
11 eqid ⊢ k ∈ A ⟼ X = k ∈ A ⟼ X
12 1 7 11 fmptdf ⊢ φ → k ∈ A ⟼ X : A ⟶ B
13 2 3 4 5 6 12 8 9 10 gsumsplit ⊢ φ → ∑ G k ∈ A X = ∑ G k ∈ A ⟼ X ↾ C + ˙ ∑ G k ∈ A ⟼ X ↾ D
14 ssun1 ⊢ C ⊆ C ∪ D
15 14 10 sseqtrrid ⊢ φ → C ⊆ A
16 15 resmptd ⊢ φ → k ∈ A ⟼ X ↾ C = k ∈ C ⟼ X
17 16 oveq2d ⊢ φ → ∑ G k ∈ A ⟼ X ↾ C = ∑ G k ∈ C X
18 ssun2 ⊢ D ⊆ C ∪ D
19 18 10 sseqtrrid ⊢ φ → D ⊆ A
20 19 resmptd ⊢ φ → k ∈ A ⟼ X ↾ D = k ∈ D ⟼ X
21 20 oveq2d ⊢ φ → ∑ G k ∈ A ⟼ X ↾ D = ∑ G k ∈ D X
22 17 21 oveq12d ⊢ φ → ∑ G k ∈ A ⟼ X ↾ C + ˙ ∑ G k ∈ A ⟼ X ↾ D = ∑ G k ∈ C X + ˙ ∑ G k ∈ D X
23 13 22 eqtrd ⊢ φ → ∑ G k ∈ A X = ∑ G k ∈ C X + ˙ ∑ G k ∈ D X