Metamath Proof Explorer


Theorem hash1n0

Description: If the size of a set is 1 the set is not empty. (Contributed by AV, 23-Dec-2020)

Ref Expression
Assertion hash1n0 ⊢ A ∈ V ∧ A = 1 → A ≠ ∅

Proof

Step Hyp Ref Expression
1 hash1snb ⊢ A ∈ V → A = 1 ↔ ∃ a A = a
2 id ⊢ A = a → A = a
3 vex ⊢ a ∈ V
4 3 snnz ⊢ a ≠ ∅
5 4 a1i ⊢ A = a → a ≠ ∅
6 2 5 eqnetrd ⊢ A = a → A ≠ ∅
7 6 exlimiv ⊢ ∃ a A = a → A ≠ ∅
8 1 7 biimtrdi ⊢ A ∈ V → A = 1 → A ≠ ∅
9 8 imp ⊢ A ∈ V ∧ A = 1 → A ≠ ∅