Metamath Proof Explorer


Theorem hlperpnel

Description: A point on a half-line which is perpendicular to a line cannot be on that line. (Contributed by Thierry Arnoux, 1-Mar-2020)

Ref Expression
Hypotheses colperpex.p ⊢ P = Base G
colperpex.d ⊢ - ˙ = dist ⁡ G
colperpex.i ⊢ I = Itv ⁡ G
colperpex.l ⊢ L = Line 𝒢 ⁡ G
colperpex.g ⊢ φ → G ∈ 𝒢 Tarski
hlperpnel.a ⊢ φ → A ∈ ran ⁡ L
hlperpnel.k ⊢ K = hl 𝒢 ⁡ G
hlperpnel.1 ⊢ φ → U ∈ A
hlperpnel.2 ⊢ φ → V ∈ P
hlperpnel.3 ⊢ φ → W ∈ P
hlperpnel.4 ⊢ φ → A ⟂ 𝒢 ⁡ G U L V
hlperpnel.5 ⊢ φ → V K ⁡ U W
Assertion hlperpnel ⊢ φ → ¬ W ∈ A

Proof

Step Hyp Ref Expression
1 colperpex.p ⊢ P = Base G
2 colperpex.d ⊢ - ˙ = dist ⁡ G
3 colperpex.i ⊢ I = Itv ⁡ G
4 colperpex.l ⊢ L = Line 𝒢 ⁡ G
5 colperpex.g ⊢ φ → G ∈ 𝒢 Tarski
6 hlperpnel.a ⊢ φ → A ∈ ran ⁡ L
7 hlperpnel.k ⊢ K = hl 𝒢 ⁡ G
8 hlperpnel.1 ⊢ φ → U ∈ A
9 hlperpnel.2 ⊢ φ → V ∈ P
10 hlperpnel.3 ⊢ φ → W ∈ P
11 hlperpnel.4 ⊢ φ → A ⟂ 𝒢 ⁡ G U L V
12 hlperpnel.5 ⊢ φ → V K ⁡ U W
13 1 4 3 5 6 8 tglnpt ⊢ φ → U ∈ P
14 4 5 11 perpln2 ⊢ φ → U L V ∈ ran ⁡ L
15 1 3 4 5 13 9 14 tglnne ⊢ φ → U ≠ V
16 1 3 7 9 10 13 5 12 hlne2 ⊢ φ → W ≠ U
17 1 3 7 9 10 13 5 4 12 hlln ⊢ φ → V ∈ W L U
18 1 3 4 5 13 9 10 15 17 16 lnrot1 ⊢ φ → W ∈ U L V
19 1 3 4 5 13 9 15 10 16 18 tglineelsb2 ⊢ φ → U L V = U L W
20 1 2 3 4 5 6 14 11 perpcom ⊢ φ → U L V ⟂ 𝒢 ⁡ G A
21 19 20 eqbrtrrd ⊢ φ → U L W ⟂ 𝒢 ⁡ G A
22 1 2 3 4 5 6 8 10 21 footne ⊢ φ → ¬ W ∈ A