Metamath Proof Explorer


Theorem hstrlem4

Description: Lemma for strong set of CH states theorem. (Contributed by NM, 30-Jun-2006) (New usage is discouraged.)

Ref Expression
Hypotheses hstrlem3.1 ⊢ S = x ∈ C ℋ ⟼ proj ℎ ⁡ x ⁡ u
hstrlem3.2 ⊢ φ ↔ u ∈ A ∖ B ∧ norm ℎ ⁡ u = 1
hstrlem3.3 ⊢ A ∈ C ℋ
hstrlem3.4 ⊢ B ∈ C ℋ
Assertion hstrlem4 ⊢ φ → norm ℎ ⁡ S ⁡ A = 1

Proof

Step Hyp Ref Expression
1 hstrlem3.1 ⊢ S = x ∈ C ℋ ⟼ proj ℎ ⁡ x ⁡ u
2 hstrlem3.2 ⊢ φ ↔ u ∈ A ∖ B ∧ norm ℎ ⁡ u = 1
3 hstrlem3.3 ⊢ A ∈ C ℋ
4 hstrlem3.4 ⊢ B ∈ C ℋ
5 1 hstrlem2 ⊢ A ∈ C ℋ → S ⁡ A = proj ℎ ⁡ A ⁡ u
6 3 5 ax-mp ⊢ S ⁡ A = proj ℎ ⁡ A ⁡ u
7 6 fveq2i ⊢ norm ℎ ⁡ S ⁡ A = norm ℎ ⁡ proj ℎ ⁡ A ⁡ u
8 eldifi ⊢ u ∈ A ∖ B → u ∈ A
9 pjid ⊢ A ∈ C ℋ ∧ u ∈ A → proj ℎ ⁡ A ⁡ u = u
10 3 9 mpan ⊢ u ∈ A → proj ℎ ⁡ A ⁡ u = u
11 10 fveq2d ⊢ u ∈ A → norm ℎ ⁡ proj ℎ ⁡ A ⁡ u = norm ℎ ⁡ u
12 eqeq2 ⊢ norm ℎ ⁡ u = 1 → norm ℎ ⁡ proj ℎ ⁡ A ⁡ u = norm ℎ ⁡ u ↔ norm ℎ ⁡ proj ℎ ⁡ A ⁡ u = 1
13 11 12 imbitrid ⊢ norm ℎ ⁡ u = 1 → u ∈ A → norm ℎ ⁡ proj ℎ ⁡ A ⁡ u = 1
14 8 13 mpan9 ⊢ u ∈ A ∖ B ∧ norm ℎ ⁡ u = 1 → norm ℎ ⁡ proj ℎ ⁡ A ⁡ u = 1
15 2 14 sylbi ⊢ φ → norm ℎ ⁡ proj ℎ ⁡ A ⁡ u = 1
16 7 15 eqtrid ⊢ φ → norm ℎ ⁡ S ⁡ A = 1