Metamath Proof Explorer


Theorem imadisjlnd

Description: Deduction form of one negated side of imadisj . (Contributed by Stanislas Polu, 9-Mar-2020)

Ref Expression
Hypothesis imadisjlnd.1 ⊢ φ → dom ⁡ A ∩ B ≠ ∅
Assertion imadisjlnd ⊢ φ → A B ≠ ∅

Proof

Step Hyp Ref Expression
1 imadisjlnd.1 ⊢ φ → dom ⁡ A ∩ B ≠ ∅
2 imadisj ⊢ A B = ∅ ↔ dom ⁡ A ∩ B = ∅
3 2 biimpi ⊢ A B = ∅ → dom ⁡ A ∩ B = ∅
4 3 necon3i ⊢ dom ⁡ A ∩ B ≠ ∅ → A B ≠ ∅
5 1 4 syl ⊢ φ → A B ≠ ∅