Metamath Proof Explorer


Theorem imasgrpf1

Description: The image of a group under an injection is a group. (Contributed by Mario Carneiro, 20-Aug-2015)

Ref Expression
Hypotheses imasgrpf1.u ⊢ U = F “ 𝑠 R
imasgrpf1.v ⊢ V = Base R
Assertion imasgrpf1 ⊢ F : V ⟶ 1-1 B ∧ R ∈ Grp → U ∈ Grp

Proof

Step Hyp Ref Expression
1 imasgrpf1.u ⊢ U = F “ 𝑠 R
2 imasgrpf1.v ⊢ V = Base R
3 1 a1i ⊢ F : V ⟶ 1-1 B ∧ R ∈ Grp → U = F “ 𝑠 R
4 2 a1i ⊢ F : V ⟶ 1-1 B ∧ R ∈ Grp → V = Base R
5 eqidd ⊢ F : V ⟶ 1-1 B ∧ R ∈ Grp → + R = + R
6 f1f1orn ⊢ F : V ⟶ 1-1 B → F : V ⟶ 1-1 onto ran ⁡ F
7 6 adantr ⊢ F : V ⟶ 1-1 B ∧ R ∈ Grp → F : V ⟶ 1-1 onto ran ⁡ F
8 f1ofo ⊢ F : V ⟶ 1-1 onto ran ⁡ F → F : V ⟶ onto ran ⁡ F
9 7 8 syl ⊢ F : V ⟶ 1-1 B ∧ R ∈ Grp → F : V ⟶ onto ran ⁡ F
10 7 f1ocpbl ⊢ F : V ⟶ 1-1 B ∧ R ∈ Grp ∧ a ∈ V ∧ b ∈ V ∧ p ∈ V ∧ q ∈ V → F ⁡ a = F ⁡ p ∧ F ⁡ b = F ⁡ q → F ⁡ a + R b = F ⁡ p + R q
11 simpr ⊢ F : V ⟶ 1-1 B ∧ R ∈ Grp → R ∈ Grp
12 eqid ⊢ 0 R = 0 R
13 3 4 5 9 10 11 12 imasgrp ⊢ F : V ⟶ 1-1 B ∧ R ∈ Grp → U ∈ Grp ∧ F ⁡ 0 R = 0 U
14 13 simpld ⊢ F : V ⟶ 1-1 B ∧ R ∈ Grp → U ∈ Grp