Metamath Proof Explorer


Theorem inlinecirc02preu

Description: Intersection of a line with a circle: A line passing through a point within a circle around the origin intersects the circle at exactly two different points, expressed with restricted uniqueness (and without the definition of proper pairs). (Contributed by AV, 16-May-2023)

Ref Expression
Hypotheses inlinecirc02p.i ⊢ I = 1 2
inlinecirc02p.e ⊢ E = I
inlinecirc02p.p ⊢ P = ℝ I
inlinecirc02p.s ⊢ S = Sphere ⁡ E
inlinecirc02p.0 ⊢ 0 ˙ = I × 0
inlinecirc02p.l ⊢ L = Line M ⁡ E
inlinecirc02p.d ⊢ D = dist ⁡ E
Assertion inlinecirc02preu ⊢ X ∈ P ∧ Y ∈ P ∧ X ≠ Y ∧ R ∈ ℝ + ∧ X D 0 ˙ < R → ∃! p ∈ 𝒫 P p = 2 ∧ p = 0 ˙ S R ∩ X L Y

Proof

Step Hyp Ref Expression
1 inlinecirc02p.i ⊢ I = 1 2
2 inlinecirc02p.e ⊢ E = I
3 inlinecirc02p.p ⊢ P = ℝ I
4 inlinecirc02p.s ⊢ S = Sphere ⁡ E
5 inlinecirc02p.0 ⊢ 0 ˙ = I × 0
6 inlinecirc02p.l ⊢ L = Line M ⁡ E
7 inlinecirc02p.d ⊢ D = dist ⁡ E
8 1 2 3 4 5 6 7 inlinecirc02p ⊢ X ∈ P ∧ Y ∈ P ∧ X ≠ Y ∧ R ∈ ℝ + ∧ X D 0 ˙ < R → 0 ˙ S R ∩ X L Y ∈ PrPairs ⁡ P
9 reueq ⊢ 0 ˙ S R ∩ X L Y ∈ PrPairs ⁡ P ↔ ∃! p ∈ PrPairs ⁡ P p = 0 ˙ S R ∩ X L Y
10 8 9 sylib ⊢ X ∈ P ∧ Y ∈ P ∧ X ≠ Y ∧ R ∈ ℝ + ∧ X D 0 ˙ < R → ∃! p ∈ PrPairs ⁡ P p = 0 ˙ S R ∩ X L Y
11 3 ovexi ⊢ P ∈ V
12 prprreueq ⊢ P ∈ V → ∃! p ∈ PrPairs ⁡ P p = 0 ˙ S R ∩ X L Y ↔ ∃! p ∈ 𝒫 P p = 2 ∧ p = 0 ˙ S R ∩ X L Y
13 11 12 mp1i ⊢ X ∈ P ∧ Y ∈ P ∧ X ≠ Y ∧ R ∈ ℝ + ∧ X D 0 ˙ < R → ∃! p ∈ PrPairs ⁡ P p = 0 ˙ S R ∩ X L Y ↔ ∃! p ∈ 𝒫 P p = 2 ∧ p = 0 ˙ S R ∩ X L Y
14 10 13 mpbid ⊢ X ∈ P ∧ Y ∈ P ∧ X ≠ Y ∧ R ∈ ℝ + ∧ X D 0 ˙ < R → ∃! p ∈ 𝒫 P p = 2 ∧ p = 0 ˙ S R ∩ X L Y