Metamath Proof Explorer


Theorem inssdif0OLD

Description: Obsolete version of inssdif0 as of 18-Jul-2026. (Contributed by NM, 27-Oct-1996) (Proof shortened by Andrew Salmon, 26-Jun-2011) (Proof shortened by Wolf Lammen, 30-Sep-2014) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion inssdif0OLD ⊢ A ∩ B ⊆ C ↔ A ∩ B ∖ C = ∅

Proof

Step Hyp Ref Expression
1 elin ⊢ x ∈ A ∩ B ↔ x ∈ A ∧ x ∈ B
2 1 imbi1i ⊢ x ∈ A ∩ B → x ∈ C ↔ x ∈ A ∧ x ∈ B → x ∈ C
3 iman ⊢ x ∈ A ∧ x ∈ B → x ∈ C ↔ ¬ x ∈ A ∧ x ∈ B ∧ ¬ x ∈ C
4 2 3 bitri ⊢ x ∈ A ∩ B → x ∈ C ↔ ¬ x ∈ A ∧ x ∈ B ∧ ¬ x ∈ C
5 eldif ⊢ x ∈ B ∖ C ↔ x ∈ B ∧ ¬ x ∈ C
6 5 anbi2i ⊢ x ∈ A ∧ x ∈ B ∖ C ↔ x ∈ A ∧ x ∈ B ∧ ¬ x ∈ C
7 elin ⊢ x ∈ A ∩ B ∖ C ↔ x ∈ A ∧ x ∈ B ∖ C
8 anass ⊢ x ∈ A ∧ x ∈ B ∧ ¬ x ∈ C ↔ x ∈ A ∧ x ∈ B ∧ ¬ x ∈ C
9 6 7 8 3bitr4ri ⊢ x ∈ A ∧ x ∈ B ∧ ¬ x ∈ C ↔ x ∈ A ∩ B ∖ C
10 4 9 xchbinx ⊢ x ∈ A ∩ B → x ∈ C ↔ ¬ x ∈ A ∩ B ∖ C
11 10 albii ⊢ ∀ x x ∈ A ∩ B → x ∈ C ↔ ∀ x ¬ x ∈ A ∩ B ∖ C
12 df-ss ⊢ A ∩ B ⊆ C ↔ ∀ x x ∈ A ∩ B → x ∈ C
13 eq0 ⊢ A ∩ B ∖ C = ∅ ↔ ∀ x ¬ x ∈ A ∩ B ∖ C
14 11 12 13 3bitr4i ⊢ A ∩ B ⊆ C ↔ A ∩ B ∖ C = ∅