Metamath Proof Explorer


Theorem int-eqineqd

Description: EquivalenceImpliesDoubleInequality generator rule. (Contributed by Stanislas Polu, 7-Apr-2020)

Ref Expression
Hypotheses int-eqineqd.1 ⊢ φ → B ∈ ℝ
int-eqineqd.2 ⊢ φ → A = B
Assertion int-eqineqd ⊢ φ → B ≤ A

Proof

Step Hyp Ref Expression
1 int-eqineqd.1 ⊢ φ → B ∈ ℝ
2 int-eqineqd.2 ⊢ φ → A = B
3 2 eqcomd ⊢ φ → B = A
4 1 3 eqled ⊢ φ → B ≤ A