Metamath Proof Explorer


Theorem invss

Description: The inverse relation is a relation between morphisms F : X --> Y and their inverses G : Y --> X . (Contributed by Mario Carneiro, 2-Jan-2017)

Ref Expression
Hypotheses invfval.b ⊢ B = Base C
invfval.n ⊢ N = Inv ⁡ C
invfval.c ⊢ φ → C ∈ Cat
invss.x ⊢ φ → X ∈ B
invss.y ⊢ φ → Y ∈ B
invss.h ⊢ H = Hom ⁡ C
Assertion invss ⊢ φ → X N Y ⊆ X H Y × Y H X

Proof

Step Hyp Ref Expression
1 invfval.b ⊢ B = Base C
2 invfval.n ⊢ N = Inv ⁡ C
3 invfval.c ⊢ φ → C ∈ Cat
4 invss.x ⊢ φ → X ∈ B
5 invss.y ⊢ φ → Y ∈ B
6 invss.h ⊢ H = Hom ⁡ C
7 eqid ⊢ Sect ⁡ C = Sect ⁡ C
8 1 2 3 4 5 7 invfval ⊢ φ → X N Y = X Sect ⁡ C Y ∩ Y Sect ⁡ C X -1
9 inss1 ⊢ X Sect ⁡ C Y ∩ Y Sect ⁡ C X -1 ⊆ X Sect ⁡ C Y
10 8 9 eqsstrdi ⊢ φ → X N Y ⊆ X Sect ⁡ C Y
11 eqid ⊢ comp ⁡ C = comp ⁡ C
12 eqid ⊢ Id ⁡ C = Id ⁡ C
13 1 6 11 12 7 3 4 5 sectss ⊢ φ → X Sect ⁡ C Y ⊆ X H Y × Y H X
14 10 13 sstrd ⊢ φ → X N Y ⊆ X H Y × Y H X