Metamath Proof Explorer


Theorem islmhmd

Description: Deduction for a module homomorphism. (Contributed by Stefan O'Rear, 4-Feb-2015)

Ref Expression
Hypotheses islmhmd.x ⊢ X = Base S
islmhmd.a ⊢ · ˙ = ⋅ S
islmhmd.b ⊢ × ˙ = ⋅ T
islmhmd.k ⊢ K = Scalar ⁡ S
islmhmd.j ⊢ J = Scalar ⁡ T
islmhmd.n ⊢ N = Base K
islmhmd.s ⊢ φ → S ∈ LMod
islmhmd.t ⊢ φ → T ∈ LMod
islmhmd.c ⊢ φ → J = K
islmhmd.f ⊢ φ → F ∈ S GrpHom T
islmhmd.l ⊢ φ ∧ x ∈ N ∧ y ∈ X → F ⁡ x · ˙ y = x × ˙ F ⁡ y
Assertion islmhmd ⊢ φ → F ∈ S LMHom T

Proof

Step Hyp Ref Expression
1 islmhmd.x ⊢ X = Base S
2 islmhmd.a ⊢ · ˙ = ⋅ S
3 islmhmd.b ⊢ × ˙ = ⋅ T
4 islmhmd.k ⊢ K = Scalar ⁡ S
5 islmhmd.j ⊢ J = Scalar ⁡ T
6 islmhmd.n ⊢ N = Base K
7 islmhmd.s ⊢ φ → S ∈ LMod
8 islmhmd.t ⊢ φ → T ∈ LMod
9 islmhmd.c ⊢ φ → J = K
10 islmhmd.f ⊢ φ → F ∈ S GrpHom T
11 islmhmd.l ⊢ φ ∧ x ∈ N ∧ y ∈ X → F ⁡ x · ˙ y = x × ˙ F ⁡ y
12 11 ralrimivva ⊢ φ → ∀ x ∈ N ∀ y ∈ X F ⁡ x · ˙ y = x × ˙ F ⁡ y
13 10 9 12 3jca ⊢ φ → F ∈ S GrpHom T ∧ J = K ∧ ∀ x ∈ N ∀ y ∈ X F ⁡ x · ˙ y = x × ˙ F ⁡ y
14 4 5 6 1 2 3 islmhm ⊢ F ∈ S LMHom T ↔ S ∈ LMod ∧ T ∈ LMod ∧ F ∈ S GrpHom T ∧ J = K ∧ ∀ x ∈ N ∀ y ∈ X F ⁡ x · ˙ y = x × ˙ F ⁡ y
15 7 8 13 14 syl21anbrc ⊢ φ → F ∈ S LMHom T