Metamath Proof Explorer


Theorem isrhmd

Description: Demonstration of ring homomorphism. (Contributed by Stefan O'Rear, 8-Mar-2015)

Ref Expression
Hypotheses isrhmd.b ⊢ B = Base R
isrhmd.o ⊢ 1 ˙ = 1 R
isrhmd.n ⊢ N = 1 S
isrhmd.t ⊢ · ˙ = ⋅ R
isrhmd.u ⊢ × ˙ = ⋅ S
isrhmd.r ⊢ φ → R ∈ Ring
isrhmd.s ⊢ φ → S ∈ Ring
isrhmd.ho ⊢ φ → F ⁡ 1 ˙ = N
isrhmd.ht ⊢ φ ∧ x ∈ B ∧ y ∈ B → F ⁡ x · ˙ y = F ⁡ x × ˙ F ⁡ y
isrhmd.c ⊢ C = Base S
isrhmd.p ⊢ + ˙ = + R
isrhmd.q ⊢ ⨣ ˙ = + S
isrhmd.f ⊢ φ → F : B ⟶ C
isrhmd.hp ⊢ φ ∧ x ∈ B ∧ y ∈ B → F ⁡ x + ˙ y = F ⁡ x ⨣ ˙ F ⁡ y
Assertion isrhmd ⊢ φ → F ∈ R RingHom S

Proof

Step Hyp Ref Expression
1 isrhmd.b ⊢ B = Base R
2 isrhmd.o ⊢ 1 ˙ = 1 R
3 isrhmd.n ⊢ N = 1 S
4 isrhmd.t ⊢ · ˙ = ⋅ R
5 isrhmd.u ⊢ × ˙ = ⋅ S
6 isrhmd.r ⊢ φ → R ∈ Ring
7 isrhmd.s ⊢ φ → S ∈ Ring
8 isrhmd.ho ⊢ φ → F ⁡ 1 ˙ = N
9 isrhmd.ht ⊢ φ ∧ x ∈ B ∧ y ∈ B → F ⁡ x · ˙ y = F ⁡ x × ˙ F ⁡ y
10 isrhmd.c ⊢ C = Base S
11 isrhmd.p ⊢ + ˙ = + R
12 isrhmd.q ⊢ ⨣ ˙ = + S
13 isrhmd.f ⊢ φ → F : B ⟶ C
14 isrhmd.hp ⊢ φ ∧ x ∈ B ∧ y ∈ B → F ⁡ x + ˙ y = F ⁡ x ⨣ ˙ F ⁡ y
15 ringgrp ⊢ R ∈ Ring → R ∈ Grp
16 6 15 syl ⊢ φ → R ∈ Grp
17 ringgrp ⊢ S ∈ Ring → S ∈ Grp
18 7 17 syl ⊢ φ → S ∈ Grp
19 1 10 11 12 16 18 13 14 isghmd ⊢ φ → F ∈ R GrpHom S
20 1 2 3 4 5 6 7 8 9 19 isrhm2d ⊢ φ → F ∈ R RingHom S