Metamath Proof Explorer


Theorem iundifdifd

Description: The intersection of a set is the complement of the union of the complements. (Contributed by Thierry Arnoux, 19-Dec-2016)

Ref Expression
Assertion iundifdifd ⊢ A ⊆ 𝒫 O → A ≠ ∅ → ⋂ A = O ∖ ⋃ x ∈ A O ∖ x

Proof

Step Hyp Ref Expression
1 iundif2 ⊢ ⋃ x ∈ A O ∖ x = O ∖ ⋂ x ∈ A x
2 intiin ⊢ ⋂ A = ⋂ x ∈ A x
3 2 difeq2i ⊢ O ∖ ⋂ A = O ∖ ⋂ x ∈ A x
4 1 3 eqtr4i ⊢ ⋃ x ∈ A O ∖ x = O ∖ ⋂ A
5 4 difeq2i ⊢ O ∖ ⋃ x ∈ A O ∖ x = O ∖ O ∖ ⋂ A
6 intssuni2 ⊢ A ⊆ 𝒫 O ∧ A ≠ ∅ → ⋂ A ⊆ ⋃ 𝒫 O
7 unipw ⊢ ⋃ 𝒫 O = O
8 6 7 sseqtrdi ⊢ A ⊆ 𝒫 O ∧ A ≠ ∅ → ⋂ A ⊆ O
9 dfss4 ⊢ ⋂ A ⊆ O ↔ O ∖ O ∖ ⋂ A = ⋂ A
10 8 9 sylib ⊢ A ⊆ 𝒫 O ∧ A ≠ ∅ → O ∖ O ∖ ⋂ A = ⋂ A
11 5 10 eqtr2id ⊢ A ⊆ 𝒫 O ∧ A ≠ ∅ → ⋂ A = O ∖ ⋃ x ∈ A O ∖ x
12 11 ex ⊢ A ⊆ 𝒫 O → A ≠ ∅ → ⋂ A = O ∖ ⋃ x ∈ A O ∖ x